What volume of 4.4 mEq/mL concentrated vial of Ca Gluconate is required to achieve 45 mEq?

To determine the required volume of a 4.4 mEq/mL concentrated vial of calcium gluconate to achieve a total of 45 mEq, you use the formula that relates the quantity of the substance (in this case, mEq), the concentration, and the volume.

The formula is:

[ \text{Volume (mL)} = \frac{\text{Desired mEq}}{\text{Concentration (mEq/mL)}} ]

Substituting the provided values into the formula gives:

[ \text{Volume (mL)} = \frac{45 \text{ mEq}}{4.4 \text{ mEq/mL}} ]

Calculating this yields:

[ \text{Volume (mL)} = \frac{45}{4.4} = 10.227 \text{ mL} ]

Rounding to two decimal places, this result is approximately 10.25 mL. This calculation confirms that to obtain a total of 45 mEq from a solution that contains 4.4 mEq in each mL, a volume of 10.25 mL is required.

This logical calculation aligns with the chosen answer, as it demonstrates the