The physician prescribes Ferrous Sulfate 500 mg to be taken daily for 30 days. If the concentration is 220 mg/5 mL, how many mL is required for one dose?

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To determine the volume of Ferrous Sulfate needed for a single dose of 500 mg when the concentration is 220 mg/5 mL, first, we need to find out how much medication is in 1 mL.

The concentration of Ferrous Sulfate is given as 220 mg in 5 mL. To find the concentration per mL, we can perform the following calculation:

220 mg / 5 mL = 44 mg/mL.

Next, to find out how many mL are required to achieve a dose of 500 mg, we can set up the equation using the concentration we just calculated:

mL required = Desired Dose (mg) / Concentration (mg/mL).

Substituting the values we have:

mL required = 500 mg / 44 mg/mL.

Calculating that gives us:

mL required = 11.36 mL.

Considering practical rounding for a liquid dosage form typically used in medications, this value rounds to approximately 11.4 mL. Therefore, the answer of 11.4 mL is correct. This calculation helps in accurately measuring the intended dose of Ferrous Sulfate, ensuring the patient receives the correct amount of

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