A solution of Halperidol contains 2 mg/mL. How many grams would be present in 473 mL of this solution?

Prepare for the Pharmacy Technician Calculations Test. Boost your skills with flashcards and multiple choice questions, enhanced with hints and explanations. Excel on your exam!

To determine the amount of Haloperidol in grams present in 473 mL of a solution that contains 2 mg/mL, you start by calculating the total milligrams of Haloperidol in the entire volume of the solution.

First, multiply the concentration of the solution by the total volume:

  • Concentration: 2 mg/mL

  • Volume: 473 mL

Calculating the total amount in milligrams involves the following arithmetic:

2 mg/mL × 473 mL = 946 mg

Next, convert milligrams to grams. Since there are 1,000 milligrams in a gram, you do this by dividing the total milligrams by 1,000:

946 mg ÷ 1,000 = 0.946 grams

Thus, the correct answer indicates that there would be 0.946 grams of Haloperidol present in 473 mL of the solution. This method of calculation is essential in pharmacy technician practice, as it reflects the critical understanding of converting between units and managing concentrations effectively in pharmaceutical preparations.

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